A Car Moving With A Speed Of 50 Km H−1 Can Be Stopped By Brakes After At Least 6 M. If The Same Car Is Moving At A Speed Of 100 Km H−1the Minimum Stopping Distance Is : (A) 12m (B) 24m (C) 6m (D) 18m

The answer is (B) 24m

Explanation:

u1 = 50\(frac{km}{hour}\)

= \(frac{50 * 1000}{60 * 60}\)

= \(frac{125m}{9sec}\)

Acceleration (a) = \(frac{u_{1}^{2}}{2s_{1}}\)

= \((frac{125}{9})^{2}\)

= \(frac{1}{2 * 6}\)

= -16 m/sec2

u2 = 100\(frac{km}{hour}\)

= \(frac{100 * 1000}{60 * 60}\)

= \(frac{25m}{9sec}\)

s2 = \(frac{-u_{2}^{2}}{2a}\)

= \(frac{-1}{2}(frac{250}{9})^{2} * -frac{1}{16}\)

= 24 m

Therefore, s2 = 24 m

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