A child walks 6 m towards the west and then 20 in towards south. He then turns east and walks another 12 m. Then he walks 12 m towards the north. How far is he from his initial position?

  1. Distance walked towards west (OA) =6m
  2. Distance walked towards south (AB) =20m
  3. Distance walked towards East (BC) =12m
  4. Distance walked towards North (CD) =12m
  5. ED = CD – CE = 20-12 = 18
  6. EO = EA – OA = 12-6 = 6

In triangle OED,

OD2 = DE2 + EO2 by Pythagoras theorem

82 + 62

= 64 + 36

= 100 ……(1)

Distance from initial point to terminal point = √100

= 10m

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question