A Compound Contains Atoms Of Three Elements A,B And C. If The Oxidation Number Of A Is +2, B Is +5 And That Of C Is −2, The Possible Formula Of The Compound Is

The formula of a compound with elements A, B, C will be of the form \( A_{x}B_{y}C_{z}, \) where x,y,z are the atomicities of individual atoms respectively.

The oxidation numbers of the elements, A, B, C are +2,+5 and −2 respectively.

A compound is always neutral, so the oxidation number of the compound is zero. Hence, the net oxidation number of the individual atoms is zero.

\(= (+2)(x) + (+5)(y) + (−2)(z) = 0 \) \( = 2x+5y−2z=0. \)

Restricting it to conditions that maximum oxidation state could be +8 or −3, by Hit and Trial method, the possible solutions of (x,y,z) could be (1,2,6) or (3,2,8).

Both the sets are possible as the elements are unknown. Hence the compounds are \( A(BC_{3})_{2} and A_{3}B_{2}C_{8} \)

Explore more such questions and answers at BYJU’S.

Was this answer helpful?


0 (0)


Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *




Free Class