A conical tent is 10 m high and the radius of its base is 24 m. Find (i) slant height of the tent. (ii) cost of the canvas required to make the tent, if the cost of 1 m2 canvas is Rs 70. (Assume π = 22/7)

Given

Height of conical tent (h) = 10m

Radius of conical base (r) = 24m

Find out

We have to find 

(i) slant height of the tent.
(ii) cost of the canvas required to make the tent, if the cost of 1 m2 canvas is Rs. 70.

Solution:

(i) slant height of the tent. 

l2 = h+ r2 [On applying Pythagoras theorem]

= (10)+ (24)2

= 676

l = 26

Therefore, the slant height of the tent = 26 m.

(ii) cost of the canvas required to make the tent, if the cost of 1 m2 canvas is Rs. 70.

Curved surface area of tent = πrl

= (22/7) × 24 × 26 m2

As cost of 1 m2 canvas = Rs 70

Cost of (13728/7)m2 canvas = (13728/7)×70 

= Rs 137280

Therefore, the cost of the canvas required to make the tent is Rs 137280.

Answer

(i) Slant height of the tent=26m

(ii) The cost of the canvas required to make the tent is Rs 137280.

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