Given:

A Copper Block Of

Mass of the copper block = 2.5 Kg = 2500g

Temperature = $500^{\circ}C$

Specific Heat Of Copper =$0.39 J/g^{-1} C$

Heat Of Fusion Of Water =$335 J/g^{-1}$

The maximum heat the copper block can lose is

$\Rightarrow Q = mC\Delta \Theta$ $\Rightarrow 2500 * 0.39 * 500$ $\Rightarrow 487500J$

Let$m_{1}g$ be the amount of ice that melts when the copper block is placed on the ice block.

The heat gained by the melted ice,$Q = m_{1}L$

Therefore, $m_{1} = \frac{Q}{L}$ $\Rightarrow m_{1} = \frac{487500}{335}$ $\Rightarrow m_{1} = 1455.22g$

Therefore, the maximum amount of ice that can melt is 1.45 kg.

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