A current of 1 A is drawn by a filament of an electric bulb. Number of electrons passing through a cross-section of the filament in 16 seconds would be roughly (a) 10^20 (b) 10^16 (c) 10^18 (d) 10^23

Answer: (a) 1020

Given parameters

  • I = 1 A
  • t = 16 sec
  • e = 1.6 × 10-19 C

Current drawn by the filament can be calculated as

I = Q/t

Since Q = N × e

I = (N×e)/t

N = (I×t)/e

N = (1 × 16)/1.6 × 10-19

N = 10 x 1019

N = 1020

Hence, number of electrons passing through a cross section of the filament in 16 seconds would be 1020.

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