A current of 9.65 Ampere flowing for 10 minutes deposits 3 g of metal which is monovalent, the atomic mass of metal is a: A.10 B. 50 C. 30 D. 96.5

Given,

Current flowing, I = 9.65 Ampere

Time = 10 min

Q = It

Q = 9.65 x 10 x 60 = 5790 C

Amount of metal deposited = 3gm

Since, the metal is monovalent, the atmoic weight will be equal to equivalent weight

Equivalent weight of metal = Wt.of metal deposited/Charge x F

= 3/5790 × 96500=50g

Atomic weight of metal = 50g

Atomic mass = 50× valency = 50×1 = 50 amu

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