A cyclist travels a distance of 1 km in the first hour, 0.5 km in the second hour and 0.3 km in the third hour. What is the average speed in (1) km/hr (2) m/sec?

Distance in one hour = 1 km

Distance in second hour = 0.5 km

Distance in third hour = 0.3 km

We know that,

Average speed = total distance /total time

i) Average speed in km/hr

ν = D/T

= 0.6km/hr

ii) Average speed in m/s

ν = 0.6* 5/8

= 0.167m/s

The average velocity is 0.6 km/hr and 0.167 m/s.

Was this answer helpful?

  
   

3.5 (5)

Upvote (8)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question