A Cyclist Turns Around A Curve At 15 Km/Hr If He Turns At Double The Speed The Tendency To Overturn Is.

We know centrifugal force F = [latex]\frac{mv^{2}}{r}[/latex]

where

v = velocity of the object

m= mass of the object

r = turning radius

As the mass and turning radius does not change in this case, we consider them as constant. Thus we can say that

centrifugal force, F = α v2

Now, as per the question, if the velocity of the cyclist is doubled, then its tendency to overturn will be increased by four times

Fα (2v)α4 v2

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