A cylindrical roller 2.5 m in length, 1.75 m in radius when rolled on a road was found to cover the area of 5500 m^2. How many revolutions did it make?

Given

length of a cylindrical roller, h = 2.5 m

radius of a cylindrical roller, r = 1.75 m

Total area rolled on a road by a cylindrical roller = 5500 m2

Hence,

Area covered by a cylindrical roller in one revolution = Curved surface area of a cylindrical roller

= 2πrh

= 2 x (22/7) x 1.75 x 2.5

= (44 x 4.375)/7

= (192.5)/7

We get,

= 27.5 m2

Number of revolutions rolled by a cylindrical roller = (Total area rolled by a cylindrical roller)/(Area rolled to cover by a cylindrical roller in one revolution)

= 5500/27.5

We get,

= 200

Therefore, the number of revolutions rolled by a cylindrical roller on a road is 200

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question