A diatomic molecule is dissociated with a radiation of 3000?. if, the bond dissociation energy of the molecule is 300kj/mol, calculate the kinetic energy of the atoms

Energy of the radiation one photon = E = hν = \(frac{hc}{lambda }\)= 6.623 ×10-34 × 3× 108 × \(frac{1}{300times {{10}^{-9}}}\)= 6.623 ×10-19J

Bond dissociation of one mole = 300kJ/mol

Bond dissociation of one molecule = \(frac{300times {{10}^{-9}}}{6.203times {{10}^{28}}}\)= 4.98 × 10-19 = 4.98 × 10-19J/molecule

Radiation energy = Bond dissociation energy – Kinetic energy

Kinetic energy = Radiation energy – Bond dissociation energy

= 6.623 ×10-19 – 4.98 × 10-19 = 1.64 × 10-19J

Kinetic energy of each atom = \(frac{KE,,of,,molecule}{2}=frac{1.64times {{10}^{-19}}}{2}\)= 8.2 × 10-20J

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