A drop of liquid of diameter 2.8 mm breaks up into 125 identical drops. The change in energy is nearly (S.T. of liquid = 75 dynes/cm) (a) zero (b) 19 erg (c) 46 erg (d) 74 erg

Given

Diameter = 2.8 mm

S.T. of liquid = 75 dynes/cm

We know that,

E = 4πR2T (n1/3-1)

On substituting the values, we get,

E = 4 x 3.14 x (1.4 x 10-1)2 x 75 (1251/3 – 1)

E = 74 erg

Therefore, the correct option is (d) 

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