# A Drop Of Solution (Volume 0.05 Ml) Contains 3×10 −6 Mole Of H+ . If The Rate Constant Of Disappearance Of H + Is 10 7 Mol Litre −1Sec −1 , How Long Would It Take For H + In The Drop To Disappear?

The concentration of drop is given by

$$\frac{Mole}{Volume in ML} * 1000$$ $$\Rightarrow \frac{3 * 10^{-6}}{0.05L} * 1000$$ $$\Rightarrow 0.06 mol litre^{-1}$$

The rate of disappearance is given by

$$\frac{Change in concentration} {Time}$$ $$\Rightarrow 1 * 10^{7} = \frac{0.06} {Time}$$

Time = $$6 * 10^{-9}sec$$

Therefore, the total time required for $$H^{+} to disappear is 6 * 10^{-9}sec$$

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