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Question

A flag pole 18m high casts a shadow 9.6m long. Find the distance of the top of the pole from the far end of the shadow.


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Solution

Let's find the length of LN in the figure.

Let MN=18m be the flag pole and its shadow be LM=9.6m

The distance of the top of the pole,N from the far end, Lof the shadow is LN.

From right-angled LMN,

LN2=LM2+MN2

On applying Pythagoras theorem we obtain

LN2=(9.6)2+(18)2LN2=9.216+324LN2=416.16LN=415.16=20.4m

Hence, the required distance is 20.4m


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