# A Force F Doubles The Length Of Wire Of Cross-section ‘A’. The Young Modulus Of Wire Is

Sol:

The Young Modulus Of Wire Is:

$$Y = \frac{F/a}{\Delta l/l}$$.

As we known,

$$\Delta l = 2l – 1 = 1$$.

$$\Rightarrow \frac{\Delta l}{l} = 1$$.

From the above formulae – $$Y = \frac{F/a}{\Delta l/l}$$.

$$Y = \frac{F/a}{1/l}$$.

$$Y = \frac{F}{a}$$.

Therefore, the Young Modulus Of Wire Is $$\frac{F}{a}$$.

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

0 (0)

(0)
(0)

#### Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.