A Force F Doubles The Length Of Wire Of Cross-section ‘A’. The Young Modulus Of Wire Is

Sol:

The Young Modulus Of Wire Is:

\( Y = \frac{F/a}{\Delta l/l} \).

As we known,

\( \Delta l = 2l – 1 = 1 \).

\( \Rightarrow \frac{\Delta l}{l} = 1 \).

From the above formulae – \( Y = \frac{F/a}{\Delta l/l} \).

\( Y = \frac{F/a}{1/l} \).

\( Y = \frac{F}{a} \).

Therefore, the Young Modulus Of Wire Is \( \frac{F}{a} \).

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