Question

A game of chance consist of spinning an arrow, which comes to rest pointing at one of the numbers $1,2,3,4,5,6,7,8$ and these are equally likely outcomes, Find the probability that the arrows will point at any factor of $8$.

Answer 1

Let's find the probability that the arrows will point at any factor of $8$.

Number of events =$1,2,3,4,5,6,7,8$

Total numbers:

$$\begin{gathered} n\left(S\right)=8 \\ Factorof8=1,2,4and8 \\ Numberoffactorn\left(E\right)=4 \\ Therefore,probability=\frac{n\left(E\right)}{n\left(S\right)}=\frac{4}{8} \\ Probability=\frac{1}{2} \end{gathered}$$

Hence, the required answer is $\frac{1}{2}$.