A gardener pushes a lawn roller through a distance 20 m. If he applies a force of 20 kg-wt in a direction inclined at 600 to the ground, the work done by him is (A) 1960 J (B) 196 J (C) 1.96 J (D) 196 kJ

Given

F = 20 kg – wt

F = 20 x 9.8 N

θ = 600 and s = 20 m

Work done = Fs cos θ

Work done = 20 x 9.8 x 20 x cos 600

On further calculation, we get,

Work done = 1960 J

Hence, the correct option is (A) 

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