A hemi spherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank. (Assume π = 22/7)


Inner Radius of the tank, (r) = 1m

The thickness of hemispherical tank = 0.01m

Therefore, the outer Radius (R) = 1 + 0.01 = 1.01m


Volume of the iron used in the tank = (2/3) π(R3– r3)

= (2/3)×(22/7) × (1.013– 13

= 0.06348 m3


The volume of the iron used in the hemispherical tank is 0.06348 m3.

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