Inner Radius of the tank, (r) = 1m
The thickness of hemispherical tank = 0.01m
Therefore, the outer Radius (R) = 1 + 0.01 = 1.01m
Volume of the iron used in the tank = (2/3) π(R3– r3)
= (2/3)×(22/7) × (1.013– 13)
= 0.06348 m3
The volume of the iron used in the hemispherical tank is 0.06348 m3.