hemispherical bowl made of brass has inner diameter 10.5cm
We have to find the cost of tin-plating it on the inside at the rate of Rs 16 per 100 cm2.
Inner radius of hemispherical bowl = 5cm
Thickness of the bowl = 0.25 cm
Outer radius of hemispherical bowl = (5+0.25) cm = 5.25 cm
We know, formula for outer CSA of hemispherical bowl = 2πr², where r is radius of hemisphere
= 2×(22/7)×(5.25)²= 173.25
Therefore, the outer curved surface area of the bowl is 173.25 cm².