Given:

A Hollow Cylinder Has A Charge q Coulomb

The Electric flux is \( Phi \)

According to the Gaussian’s law:

let the flux on A, B and C be \( Phi _{A},Phi _{B},Phi _{C}\)

Then the

net \(Phi = Phi _{A} + Phi _{B} + Phi _{C} = frac{q}{varepsilon _{0}}\)

We get

\(Phi _{A} = Phi _{C} \)

Thus,

\( 2Phi + Phi = frac{q}{varepsilon _{0}} Rightarrow Phi _{A} = frac{1}{2} (frac{q}{varepsilon} – Phi) \)

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