A joker’s cap is in the form of right circular cone of base radius 7 cm and height 24cm. Find the area of the sheet required to make 10 such caps. (Assume π = 22/7)


Radius of conical cap (r) = 7 cm

Height of conical cap (h) = 24cm

Find out

We have to find the area of the sheet required to make 10 such caps. 


Slant height, l2 = r2+h2

= 72+242

= 49+576

= 625 [Taking square root on both the side]

l = 25 cm

Curved surface area of 1 conical cap = πrl

= (22/7)×7×24

= 550

Curved surface area of 10 caps = (10×550) cm2 = 5500 cm2


Therefore, the area of 5500 cm2 of the sheet is required to make 10 such caps.

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