P is the position of the kite. Its height from the point Q (on the ground)= PQ = 60m.

Let OP= l be the length of the string.

\(\angle P O Q = 60^{\circ}\) \(sin\Theta = \frac{Opposite}{Hypotenuse}\) \(\frac{PQ}{OP} = sin 60^{\circ}\) \(\frac{60}{L} = sin 60^{\circ} = \frac{\sqrt{3}}{2}\) \(\frac{60}{L} = \frac{\sqrt{3}}{2}\) \(L = \frac{3 * 2 * 20}{\sqrt{3}}m\) \(L = 40\sqrt{3}m\)

Therefore, the length of the string is \(40\sqrt{3}m\).

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