A lead bullet of mass 2 Kg, travelling with a velocity of 20 m/s, comes to rest after penetrating 20m in a still target. Find the resistive force applied by the target and acceleration of the bullet.

We know that, v2 = u2 – 2 as

v = 0 m/s

u = 20 m/s, s = 20m

Acceleration = 40 m/s2

So, F = – ma (resistive force)

F = – 80 N

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