A long solenoid has 500 turns. When a current of 2 amperes is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10-3 Web. The self-inductance of the solenoid is (1) 1.0 henry (2) 4.0 henry (3) 2.5 henry (4) 2.0 henry

A long solenoid has 500 turns. When a current of 2 amperes is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10-3 Web. The self-inductance of the solenoid is (1) 1.0 henry (2) 4.0 henry (3) 2.5 henry (4) 2.0 henry

Answer: (1) 1.0 henry

A solenoid is a coil of wire tied across a piston, mostly made of iron, in the form of a corkscrew.

  • Like with all electromagnets, when an electric current passes via the wire a magnetic field is generated.
  • The magnetic field of an activated solenoid has both positive and negative poles that attract or repel sensitive material to the magnets.
  • The electrical force causes the piston to shift either forward or backward inside a solenoid that’s how a solenoid coil creates motion.

Given parameters:

  • Number of turns = 500
  • Current (I) = 2A

Solution:

Flux linkage = Flux through each number of turns

ϕ = 500 × 4 × 10-3

ϕ = 2Wb

Since ϕ = LI

L = ϕ /I

L = 2/2

L = 1 H

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