A man starts his job with a certain monthly salary and earns a fixed increment every year. If his salary was Rs 1500 after 4 year of service and Rs 1800 after 10 years of service, what was his starting salary and what is the annual increment?

Let Rs x be the starting salary of a man and Rs y be the fixed annual increment.

Then,

Salary after 4 years of service = Rs (x + 4y)

Salary after 10 years of service = Rs (x + 10y)

As per the question, given that,

(x + 4y) = Rs 1500 ……(1)

(x + 10y) = Rs 1800 ……(2)

On subtracting equation (1) from equation (2), we get,

6y = 300

y = 300/6

we get,

y = 50

Substituting y = 50 in equation (1), we get,

x + 4(50) = 1500

x + 200 = 1500

x = 1500 – 200

x = 1300

Therefore, the starting salary of a man was Rs 1300 and annual increment is Rs 50

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