A metal conductor of length 1 m rotates vertically about one of its ends at angular velocity 5 radians per second. If the horizontal component of earths's magnetic field is 0.2 x 10-4 T, then the e.m.f developed between the two ends of the conductor is (A) 5 μV (B) 50 μV (C) 5 mV (D) 50 mV

Given

l = 1 m

ω = 5 rad/s

B = 0.2 x 10-4 T

ε = Bωl2/2

ε = {0.2 x 10-4 x 5 x (1)2}/2

We get,

ε = 50 μV

Hence, the correct option is (B) 

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