A metal pipe is 77 cm long. The inner diameter of a cross section is 4 cm, the outer diameter being 4.4cm. (see fig.) . Find its (i) inner curved surface area, (ii) outer curved surface area (iii) total surface area (Assume π = 22/7)

Given

 Height of Cylindrical metal pipe (h) =77 cm

The inner diameter of metal pipe (d)=4cm,

The outer diameter of metal pipe (D)=4.4cm, 

Find out

We have to find 

(i) inner curved surface area,

(ii) outer curved surface area

(iii) total surface area

Solution:

The inner diameter of metal pipe (d)=4cm,

Hence, inner radius(r)=d/2=2 cm

The outer diameter of metal pipe (D)=4.4cm, 

Hence, outer radius(R)=D/2=2.2 cm

Inner curved surface area=2πrh =2*(22/7)*2*77

=968 cm2 

Outer curved surface area=2πrh =2*(22/7)*2.2*77

 =1064.8 cm2

Total Surface Area=Inner curved surface area+Outer curved surface area+area of two bases

As pipe is hollow, area of two bases is a ring area given by=2(πR2-πr2) = 2π(R2-r2)

 =968+1064.8+2×(22/7)×(2.22-22)

= 2031.8+5.28

= 2038.08 cm2

Answer

Hence, Total surface area =2038.08 cm2

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