A meter bridge is set-up as shown, to determine an unknown resistance. X using a standard 10 ohm resistor. The galvanometer shows null point when tapping key is a 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of X is: A. 10.2ohm B. 10.6ohm C. 10.8ohm D. 11.1ohm

Answer: B. 10.6 ohm

By using the condition for balanced Wheatstone bridge, we have:

X/10 = (52 + 1)cm/(100- 52 +2)cm = 53/50

X = (53×10)/50 = 10.6 ohm

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question