A meter bridge is set-up as shown, to determine an unknown resistance. X using a standard 10 ohm resistor. The galvanometer shows null point when tapping key is a 52 cm mark. The end-corrections are 1 cm and 2 cm respectively for the ends A and B. The determined value of X is: A. 10.2ohm B. 10.6ohm C. 10.8ohm D. 11.1ohm

Answer: B. 10.6 ohm

By using the condition for balanced Wheatstone bridge, we have:

X/10 = (52 + 1)cm/(100- 52 +2)cm = 53/50

X = (53×10)/50 = 10.6 ohm

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