A Millivoltmeter Of 25 Millivolt Range Is To Be Converted Into An Ammeter Of 25-ampere Range. The Value (In Ohm) Of Necessary Shunt Will Be: (A) 1 (B) 0.01 (C) 0.05 (D) 0.001

The correct answer is (D) 0.001

\( i_{g} = \frac{25 mV}{G} ampere \)

Where G is the resistance of the meter. The value of the shunt required for converting it into ammeter of range 25 A will be

\( S = \frac{i_{g}G}{i – i_{g}} \) \( \Rightarrow \frac{25 mV}{25} \) \( \Rightarrow 0.001 \Omega \)

Hence, proved

Explore more such questions and answers at BYJU’S.

Was this answer helpful?

 
   

0 (0)

(0)
(0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question