CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A motorcyclist wants to drive on the vertical surface of a wooden well of radius 5m, with a minimum speed of 55. The minimum value of coefficient of friction between the tyres and the wall of the wood must be: (Take g=10m/s2)


A

0.10

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

0.20

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

0.30

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

0.40

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D

0.40


Step 1: Given

The radius of the well: r=5m

Minimum speed: v=55

Acceleration due to gravity: g=10m/s2

Step 2: Formula Used

Frictional Force: F=mg

Centripetal force: N=mv2r

Coefficient of friction: μ=FN

Step 3: Calculating coefficient of friction

Substitute F=mg and N=mv2r in μ=FN.

μ=FN=mgmv2r=grv2

Substitute the values in the obtained equation to calculate the coefficient

μ=10×5552=50125=25=0.40

Hence, option D is correct.


flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
All Strings Attached
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon