A motorcyclist wants to drive on the vertical surface of a wooden wall of radius 5m, with a minimum speed of 5√5. The minimum value of coefficient of friction between the tyres and the wall of the wood must be: (Take g = 10 ms^-2) (A) 0.10 (B) 0.20 (C) 0.30 (D) 0.40

Given

A motorcyclist wants to drive on the vertical surface of a wooden wall of radius 5m, with a minimum speed of 5√5

To find the minimum value of coefficient of friction between the tyres and the wall of the wood

Friction force, f = mg

Centripetal force, N = mV2/r

Therefore,

μ = f/N

μ = mg/(mV2/r)

μ = rg/V2

μ = (5 x 10)/(5√5)2

μ = 50/125

We get,

μ = 0.40

Hence, the minimum value of coefficient of friction between the tyres and the wall of the wood is 0.40

So, the correct option is (D)

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