A Particle Moves Along X-axis In Such A Way That Its Coordinate (X) Varies With Time (T) According To The Expression, X=2−5T+6T 2 . Then The Initial Velocity Of The Particle Is

Given:

[latex] x = 2 – 5t + 6t^{2}[/latex]

The displacement is given as

[latex] y = ut + \frac{1}{2}at^{2}[/latex]

Here

u = initial velocity

a = acceleration

[latex] \Rightarrow y = – 5t + 6t^{2} + 2[/latex]

Therefore,

u = -5m/s

[latex] a = 12m/s^{2}[/latex] [latex] \therefore Initial velocity, u = -5m/s[/latex]

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