# A Particle Moves Along X-axis In Such A Way That Its Coordinate (X) Varies With Time (T) According To The Expression, X=2−5T+6T 2 . Then The Initial Velocity Of The Particle Is

Given:

$x = 2 – 5t + 6t^{2}$

The displacement is given as

$y = ut + \frac{1}{2}at^{2}$

Here

u = initial velocity

a = acceleration

$\Rightarrow y = – 5t + 6t^{2} + 2$

Therefore,

u = -5m/s

$a = 12m/s^{2}$ $\therefore Initial velocity, u = -5m/s$

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