Question

A patient in a hospital is given soup daily in a cylindrical bowl of diameter $7cm$. If the bowl is filled with soup to a height of $4cm$, how much soup the hospital have to prepare daily to serve $250$ patients.

Answer 1

Radius of the cylindrical bowl $=\frac{7}{2}cm$,

Height of the cylindrical bowl $=4cm$
Volume of the cylindrical bowl $={\mathrm{\pi r}}^2\mathrm{h}$

$=\frac{22}{7}\times {\left(\frac{7}{2}\right)}^2\times 4$

$=\frac{22}{7}\times \frac{7}{2}\times \frac{7}{2}\times 4$
$=22\times 7=154c{m}^3$

Volume of the soup given to $250$ patients $=250\times 154$
$=38,500c{m}^3$
$=\frac{38500}{1000}=\frac{385}{10}=38.5litres$ Note -: $1litre=1000c{m}^3$
Therefore, volume of the soup given to $250$ patients $=38.5litres$