A person of mass 50 kg stands on a weighing scale oil a lift if the lift is descending with a downward acceleration of 9 ms^-2. what would be the reading of the weighing scale

It can be considered that reading of the weighing scale is equal to the apparent weight of the person.

Therefore, R = m (g -a) = 50 (10-9) = 50N = 5kg

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