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Question

A person of mass 50kg stands on a weighing scale on a lift if the lift is descending with a downward acceleration of 9ms2. what would be the reading of the weighing scale


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Solution

Step 1: Given

Mass of the person = 50kg

Downward acceleration of lift = 9ms2

Step 2: Find the reading on the weighing scale.

Reading on a weighing scale is equal to the apparent weight.

R=m(g-a)R=50(10-9)R=50kN

Hence, the reading is 50kN.


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