A Potentiometer Wire Of Length L And A Resistance R Are Connected In Series With A Battery Of E.M.F. E0 And A Resistance R1. An Unknown E.M.F. E Is Balanced At A Length L Of The Potentiometer Wire. The E.M.F. E Will Be Given By.

E.M.F

 

The current through the potentiometer wire is

\(I = \frac{E_{0}}{r + r_{1}}\)

The potential difference across the wire is

\(V = Ir = \frac{E_{0}r}{r + r_{1}}\)

The potential gradient along the potentiometer wire is

\(k = \frac{V}{L} = \frac{E_{0}r}{r + r_{1}L}\)

E is balanced against length l of the potentiometer wire

\(kl = \frac{E_{0}r}{r + r_{1}L}\)

Therefore, the unknown e.m.f. is\( \frac{E_{0}r}{r + r_{1}L}\)

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