A racing car has a uniform acceleration of 4m/s square. What distance will it cover in 10sec after start?

Answer:

A racing car has a uniform acceleration of 4m/s square, it will cover 200m in 10sec after start.

Given

  • The initial velocity (u) = 0
  • The acceleration (a) = 4m/s
  • Time (t) = 10 sec

Need to find

The final velocity (v) = ?

Solution

Motion is the phenomenon in which an object changes its position. The first equation of motion is given as:

v = u + at

Where,

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • t = time taken

Substitute the given parameters in the above equation.

v = 0 + 4 × 10

v = 0 + 40

v = 40m/s

The third equation of motion is given as:

 = 

Where,

  • v = final velocity
  • u = initial velocity
  • a = acceleration
  • t = time taken

Substitute the known parameters in the above equation.

(40)2 = 2 x 4 x s

1600 = 8s

s = 1600/8

s = 200 m

∴ Distance it will cover in 10sec after start is 200m

Check out the video below for more information on motion

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