A racing car has a uniform acceleration of 4m/s square. What distance will it cover in 10sec after start?

The initial velocity = u = 0

The final velocity = v

The acceleration = a and time = t = 10

a = 4

The first equation of motion i.e -v=u+at

v = 0 + 40

v = 40m/s

Thethird equation of motion i.e-2as=v2– u2

2 x 4 x s = 1600

s + 1600/8 = 200m

∴Distance it will cover in 10sec after start is 200m

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