A Radio Transmitter Operates At A Frequency Of 880 Khz And Power Of 10 kW. The Number Of Photons Emitted Per Second Is :

Given:

Power of transmitter = 10kW

Power P = 10kW = \( 10 * 10^{3} W\)

Frequency of the transmitter = 880 kHz

Frequency v = 880 kHz =\( 880 * 10^{3} Hz\)

The number of photons emitted per second is :

\( N = \frac{P}{hv}\) \( = \frac{10 * 10^{3}}{6.6 * 10^{-34} * 880 * 10^{-3}}\) \( = 1.71 * 10^{31}\)

Therefore, the number of photons emitted per second is \( 1.71 * 10^{31}\)

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