A sample of air is saturated with benzene (vapour pressure =100 mm Hg at 298 K) at 298K, 750mm Hg pressure. If it is isothermally compressed to one third of its initial volume, the final pressure of the system is:

The total pressure = vapour pressure of benzene + pressure of air. The pressure of air =750−100=650 mm of Hg. The mixture is compressed to one-third of its volume. Now, Since, P∝V1 So, the pressure of the air after compression, Pf=650×3 mm of Hg=1950 mm of Hg The final total pressure PT=(1950+100)=2050 mm of Hg. =2050 torr Therefore, 1 mm of Hg ≈ 1 torr

Was this answer helpful?

  
   

0 (0)

Upvote (0)

Choose An Option That Best Describes Your Problem

Thank you. Your Feedback will Help us Serve you better.

Leave a Comment

Your Mobile number and Email id will not be published. Required fields are marked *

*

*

BOOK

Free Class

Ask
Question