A shopkeeper sells a table at 8% profit and a chair at a 10% discount, thereby getting Rs 1008. If he had sold the table at 10% profit and the chair at 8% discount, he would have got Rs. 20 more. Find the cost price of the table and the list price of the chair.

Cost price of chair = x

Cost price of table = y

Case I

Selling price of table = y + (8y / 100) = (108 / 100) y

Cost price of chair = x – (10 / 100) x = (9 / 10) x

According to question, (108 / 100) y + (9 / 10) x = 1008

108y + 90x = 100800

6y + 5x = 5600 —– (1)

Case II

Selling price of chair = y + (10 / 100) y = (11 / 10) y

Selling price of table = x – (8 / 100) x = (92 / 100) x

According to question

(11 / 10) y + (92 / 100) x = 1028

110y + 92x = 102800 ——- (2)

Solving equation 1 and 2,

x = 400

y = 600

Cost of chair = 400 Rs

Cost of table = 600 Rs.

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