A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.

Answer: 1 : 182.41

Mass of silver = m g

Mass of gold = m /100g

\(Number\, of\, atoms\, of\, silver = \frac{Mass}{Atomic\, mass}\times N_{A}\)

Number of atoms of silver = (m /108) × NA

Number of atoms of gold = m / (100 × 197) × NA

The ratio of number of atoms of gold to silver = Au: Ag

The ratio of number of atoms of gold to silver = m/(100 × 197) × NA: m/ 108 × NA

The ratio of number of atoms of gold to silver = 108: 100 × 197

The ratio of number of atoms of gold to silver = 108: 19700

The ratio of number of atoms of gold to silver = 1: 182.41

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