A Simple Harmonic Motion Is Represented By X(t) = sin2 Omega T - 2 Cos2 Omega T.What Is The Angular Frequency Of Oscillation?

x = \(sin^{2} \omega t – 2 cos^{2}\omega t\)

= 1 – 3 \(cos^{2} \omega t\)

= 1 – 3\( (\frac{1 + cos 2 \omega t}{2})\)

=\( -\frac{1}{2} – \frac{3}{2}cos 2 \omega t\)

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