A solid iron cuboidal block of dimensions 4.4m�2.6m�1m is cast into a hollow cylindrical pipe of internal radius 30 cm and thickness 5 cm. Find length of the pipe?

Given that

internal radius of hollow cylindrical pipe, r = 30 cm
Thickness of the hollow cylindrical pipe , w = 5 cm

Let length of the hollow cylindrical pipe be= h
External radius, R = 30 + 5 = 35 cm
Hence volume of cuboid = volume of hollow cylinder
440 × 260 ×100 = π(R2 – r2) h
440 × 260 × 100 = 22/7(352 – 302)h
⇒ 440 × 260 × 100 = 22/7(325)h
∴ h = 11200 cm = 112 m

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