The moment of inertia of a solid sphere is \( \frac{2}{5}MR^{2}\)

The moment of inertia of a disc is \( \frac{1}{2}MR^{2}\)

The moment of inertia of a disc through its edge is {1}{2}MR^{2} + MR^{2}\)

As both moment of inertia are equal

\( \Rightarrow {2}{5}MR^{2} + {3}{2}MR^{2}\)

Therefore,\( r = \frac{2R}{\sqrt{15}}\)

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