Mole fraction of pentane solution =\( \frac{1}{1 + 4} = \frac{1}{5} \)

Mole fraction of hexane solution =\( \frac{4}{1 + 4} = \frac{1}{5} \)

The total pressure of the solution,

\( P_{s} = X_{P}P_{P}^{O} + X_{H}P_{P}^{O} \) \( \Rightarrow \frac{1}{5} * 440 mm Hg + \frac{4}{5} * 120 mm Hg \) \( \Rightarrow 184 mm Hg \)

Therefore, the fraction of pentane in the vapour phase.

\( \Rightarrow \frac{X_{P}P_{P}^{O}}{P_{s}} \) \( \Rightarrow\frac{88}{184} \) \( \Rightarrow 0.478 \)

Therefore, the mole fraction of pentane in the vapour phase would be 0.478

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