A solution of cuso4 is electrolysed for 10 minutes with a current of 1.5 amperes. what is the mass of copper deposited at the cathode?

The reaction can be written as

Cu2+ + 2e- –>Cu(s)

Q = I*t

I = 1.5Ampere

Time t = 10*60s = 600sec

therefore applying in the equation Q = 1.5*600

= 900C

2F amount of electricity deposit copper =63.5

F = 96500

therefore 900C amount of electricity deposit copper

=63.5*900/2*96500

=0.296g

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