A Spring Of Force Constant 800 N/m Has An Extension Of 5 Cm Find Work

Given data:

A spring of force constant = 800N/m

We have to find the work done in extending it from 5cm to 15cm

Work done = change in energy stored in the spring.

Work done = \(frac{1}{2} * k (x_{2}^{2} – x_{1}^{2}) \)

As given in the question

x1 = 5cm

x2 = 15cm

Force constane k = 800N/m = 800/100 N/cm = 8N/cm

W = \(frac{1}{2} * 8(15^{2} – 5^{2}) \) = \(frac{1}{2} * 8(225-5)\)

W = \(frac{1}{2} * 8 * 200\)

W = 800Ncm = 8 Nm = 8J

Therefore, Work done in extending it from 5cm to 15cm is 8J

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