A spy report about a suspected car reads as follows. "The car moved 2.00 km towards the east, made a perpendicular left turn, ran for 500 m, made a perpendicular right turn, ran for 4.00 km and stopped". Find the displacement of the car.

Consider East direction is indicated as i west direction is indicated as −i North direction is indicated as j South direction is indicated as −j Motion initially 2km towards the east =2i Then left turn means north and 0.5km =0.5j Then a right turn means east and 4.0km =4i Net displacement will be 2i+0.5j+4i=6i+0.5j \(\sqrt{6^{2}+(0.5)^{2}} = 6.02 Kms\)

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