# A Stone Falls Freely From Rest From A Height H And It Travels A Distance

The flight is of time t then height fallen in time t will be h = $$\frac{1}{2} gt^{2}$$

The height fallen in time t−1 second will be $$h_{1} = \frac{1}{2} g(t – 1)^{2}$$

The displacement of last second will be $$h – h_{1} = \frac{g}{2} (t^{2} – ^{2} – 1 + 2t)$$

As given

$$\frac{h – h_{1}}{h} = \frac{9}{25}$$

By solving the above equation, we get

$$\frac{2t – 1}{t^{2}}$$ $$\Rightarrow \frac{9}{25}$$

Now t = 5 seconds

so, h = $$\frac{1}{2} * 9.8 * 5^{2}$$ $$\Rightarrow 122.5 meter$$

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