CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A stone falls from a cliff and travels 24.5m in the last second before it reaches the ground at the foot of the clif. Find the height of the cliff. (g=9.8ms-2)


Open in App
Solution

Step 1: Given

Distance traveled in the last second = 24.5m

Acceleration due to gravity g=9.8ms-2

Step 2: Formula

sn=u+g(n-12)s=ut+12gt2

Step 3: Calculation of time

sn=u+g(n-12)24.5=0+9.8(n-12)24.5=9.8n-4.99.8n=24.5+4.9n=29.49.8n=3

So time taken to reach the ground is 3s.

Step 4: Calculation of height

s=ut+12gt2=0×3+12×9.8×32=4.9×9=44.1m

So, the height of the cliff is 44.1m.


flag
Suggest Corrections
thumbs-up
37
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon