A stone is dropped from a tower at a height of . Another stone is thrown up simultaneously from the ground, which can reach a maximum height of . Determine the time at which both the stones meet.
Step 1: Given data
Step 2: To find
Time at which both the stones meet.
Step 3: Calculate the time of the meeting:
Use the second equation of motion to find the height, .
Let the initial velocity of the stone that is thrown from the ground .
At maximum height , Velocity
Let be the distance covered by the stone which is dropped from height and be the distance covered by the stone which is thrown up from the ground.
Let time both stones crossed each other.
Adding and gives the height .
Add equations (1) and (2).
Hence, the time at which both the stones meet is .