A stone is dropped from a tower at a height of h. Another stone is thrown at a height of 4h. Determine the time at which both the stones meet.

S₁ = \(frac{1}{2}gt^{2}\)

S₂ = \(ut-frac{1}{2}gt^{2}\)

S₁ + S₂ = h

4h = \(frac{u^{2}}{2g}\)

u = \(sqrt{8gh}\)

ut = h

\(sqrt{8ght}\) = h

t = \(sqrt{frac{h}{8g}}\)

Related Questions & Answers
Define Resistance	How Can Galvanic Corrosion Be Prevented
List 4 Functions Of Fat	What Are The Benefits Of Lactic Acid Bacteria
Explain The Meaning Of Malleable And Ductile	Give An Example Of A Plant Which Bear Naked Seeds
How Many Island Countries Are Neighbours Of India	The Climate Of India Is Strongly Influenced By Which Winds
Write 5 Functions Of Saliva	A Tadpole Develops Into A Frog By The Process Of