A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m s-2 and speed of sound = 340 m s-1.

Height of the tower, s = 500 m
Velocity of sound, v = 340 m sˆ’1
Acceleration due to gravity, g = 10 m sˆ’2
Initial velocity of the stone, u = 0 (since the stone is initially at rest)
Time taken by the stone to fall to the base of the tower, t1
According to the second equation of motion:
S = ut1 + 1/2gt12
500 = 0 x t1 + 1/2 x 10 x t12
t12 = 100
t1 = 10s
Now, time taken by the sound to reach the top from the base of the tower, t2= 500/340 = 1.47 s
Therefore, the splash is heard at the top after time, t
Where, t= t1 + t2 = 10 + 1.47 = 11.47 s.

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